document.write( "Question 629008: Find the x-intercept(s) of the graph of the function without graphing the function.\r
\n" ); document.write( "\n" ); document.write( " \"+f%28x%29+=+sqrt%282x%2B21%29-+sqrt%282x%29-3+\"
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Algebra.Com's Answer #395969 by reviewermath(1029)\"\" \"About 
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\"sqrt%282x%2B21%29-+sqrt%282x%29-3+=+0\"
\n" ); document.write( "\"sqrt%282x%2B21%29+=++sqrt%282x%29+%2B+3\", square both sides
\n" ); document.write( "\"2x+%2B+21+=+2x+%2B+6sqrt%282x%29+%2B+9\"
\n" ); document.write( "\"6sqrt%282x%29+=+12\"
\n" ); document.write( "\"sqrt%282x%29+=+2\", square both sides
\n" ); document.write( "\"2x+=+4\"
\n" ); document.write( "\"x+=+2\"
\n" ); document.write( "The x-intercept is 2.
\n" ); document.write( "Coordinates: (2,0)
\n" ); document.write( "To verify, here's the graph:
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-1%2C+10%2C+-5%2C+4%2C+sqrt%282x%2B21%29-+sqrt%282x%29-3%29+\"
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