document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57933>Question 57933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am a first year algebra student in the eighth grade.  I am having a great deal of difficulty in this subject as I am not able to pull higher than a C on a test and sometimes I do worse than that.  I am doing a study guide right now for a test I am supposed to take tomorrow but I am stuck.  Could you please help me in explaining the steps of this equation?  THis is not from a textbook.  It is from a worksheet/studyguide.   \r<BR>\n" );
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document.write( "                              12g-2g=250<BR>\n" );
document.write( "  I think I would do this,   <BR>\n" );
document.write( "    12g - 2g = 250<BR>\n" );
document.write( "     12 x g - 2 x g = 250<BR>\n" );
document.write( "      This is where I am confused, would it be (12 x g) - 2 - (2 x g) - 2 =250<BR>\n" );
document.write( "                                     and then   (12 x g) - g =250<BR>\n" );
document.write( "Now I am not sure what comes next....could you please help me.....I have many more to do on this worksheet to be handed in tomorrow but more importantly, I will have this type of problem on the test.  Thank you for any help you can give me. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39596 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12g-2g=250 [Combine like-terms (example, combine all of the g's)]<BR>\n" );
document.write( "10g=250<BR>\n" );
document.write( "10/10g=250/10<BR>\n" );
document.write( "g=25<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check by plugging (g=25) back into the original equation]<BR>\n" );
document.write( "12(25)-2(25)=250<BR>\n" );
document.write( "300-50=250<BR>\n" );
document.write( "250=250 [Checks out]<BR>\n" );
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