document.write( "Question 628981: A freight train made two 180 km trips. It made the second trip in 3 hours less time by increasing the rate of travel by 10km/h. Find each rate at which the train left. \n" ); document.write( "
Algebra.Com's Answer #395954 by josmiceli(19441)\"\" \"About 
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1st trip:
\n" ); document.write( "\"+d+=+r%2At+\"
\n" ); document.write( "(1) \"+180+=+r%2At+\"
\n" ); document.write( "2nd trip:
\n" ); document.write( "(2) \"+180+=+%28+r+%2B+10+%29%2A%28+t+-+3+%29+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "(2) \"+180+=+r%2At+%2B+10t+-+3r+-+30+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+r+=+180%2Ft+\"
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+180+=+%28180%2Ft%29%2At+%2B+10t+-+3%2A%28180%2Ft%29+-+30+\"
\n" ); document.write( "(2) \"+180+=+180+%2B+10t+-+3%2A%28180%2Ft%29+-+30+\"
\n" ); document.write( "(2) \"+0+=++%2B+10t+-+3%2A%28180%2Ft%29+-+30+\"
\n" ); document.write( "(2) \"+30+=+10t+-+3%2A%28180%2Ft%29+\"
\n" ); document.write( "Multiply both sides by \"+t+\"
\n" ); document.write( "(2) \"+30t+=+10t%5E2+-+540+\"
\n" ); document.write( "(2) \"+10t%5E2+-+30t+-+540+=+0+\"
\n" ); document.write( "(2) \"+t%5E2+-+3t+-+54+=+0+\"
\n" ); document.write( "(2) \"+%28+t+-+9+%29%2A%28+t+%2B+6+%29+=+0+\"
\n" ); document.write( "Since \"+t+\" must be positive,
\n" ); document.write( "\"+t+=+9+\" is the answer
\n" ); document.write( "---------------------
\n" ); document.write( "(1) \"+180+=+r%2At+\"
\n" ); document.write( "(1) \"+180+=+r%2A9+\"
\n" ); document.write( "(1) \"+r+=+180%2F9+\"
\n" ); document.write( "(1) \"+r+=+20+\"
\n" ); document.write( "\"+r+%2B+10+=+30+\"
\n" ); document.write( "The rate for the 1st trip was 20 km/hr
\n" ); document.write( "The rate for the 2nd trip was 30 km/hr
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+180+=+%28+r+%2B+10+%29%2A%28+t+-+3+%29+\"
\n" ); document.write( "(2) \"+180+=+%28+20+%2B+10+%29%2A%28+9+-+3+%29+\"
\n" ); document.write( "(2) \"+180+=+30%2A6+\"
\n" ); document.write( "(2) \"+180+=+180+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );