document.write( "Question 628942: tan^2x + cot^2x = 1 - 2sin^2x + 2sin^4x / sin^2x - sin^4x \n" ); document.write( "
Algebra.Com's Answer #395948 by Alan3354(69443)\"\" \"About 
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tan^2x + cot^2x = 1 - 2sin^2x + 2sin^4x / sin^2x - sin^4x
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