document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57924>Question 57924</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1888469544/algebrahomeworkh>beginning algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> -2[3a-2(4a-1)]+2=2a+3-3  please help me solve this problem i am having alot of trouble.   thanks much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39593 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39593\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2[3a-2(4a-1)]+2=2a+3-3 [Use the order of operations (PEMDAS) to solve]<BR>\n" );
document.write( "-2[3a-8a+2]+2=2a+3-3<BR>\n" );
document.write( "-2[-5a+2]+2=2a+0<BR>\n" );
document.write( "10a-4+2=2a<BR>\n" );
document.write( "10a-2=2a [Solve for a]<BR>\n" );
document.write( "10a-10a-2=2a-10a<BR>\n" );
document.write( "-2=-8a<BR>\n" );
document.write( "-2/-8=a<BR>\n" );
document.write( "1/4=a<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check by plugging (a=1/4) back into the original equation. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );