document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628834>Question 628834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The height of a new building in China will be 859 feet. Neglecting air resistance, the height of an object dropped from this building at time t seconds would be given by the polynomial -16t^2+859. Find the height of the object at time t=4 seconds.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395880 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just plug in 4 for t<BR>\n" );
document.write( "-16t^2+859<BR>\n" );
document.write( "-16*4^2+859<BR>\n" );
document.write( "859-256<BR>\n" );
document.write( "603\r<BR>\n" );
document.write( "\n" );
document.write( "BTw to find out how long it would take to reach the ground set it to zero<BR>\n" );
document.write( "-16t^2+859=0 and solve for t<BR>\n" );
document.write( "859=16t^2<BR>\n" );
document.write( "859/16=t^2<BR>\n" );
document.write( "sqrt(859)/4=t<BR>\n" );
document.write( "7.32 =t<BR>\n" );
document.write( "It will take about 7.32 seconds to hit the ground.<BR>\n" );
document.write( " </SPAN>\n" );
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