document.write( "Question 628819: I'm trying to find the answer to this question \"A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 300 feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed?\" \n" ); document.write( "
Algebra.Com's Answer #395866 by Alan3354(69443)\"\" \"About 
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\"A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 300 feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed?\"
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\n" ); document.write( "Area = L*W
\n" ); document.write( "L + 2W = 300 --> L = 300 - 2W
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\n" ); document.write( "Area = W*(300 - 2W) = 300W - 2W^2
\n" ); document.write( "Area = f(W) = -2W^2 + 300W
\n" ); document.write( "That's a parabola whose vertex is the maximum
\n" ); document.write( "The axis of symmetry is W = -b/2a = -300/(-4)
\n" ); document.write( "W = 75 ft for max area
\n" ); document.write( "L = 150 ft
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\n" ); document.write( "Area = 75*150 = 11250 sq ft
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