document.write( "Question 628760: what is the center (h,k) of 3x^2+12x+3y^2=0 \n" ); document.write( "

Algebra.Com's Answer #395829 by nerdybill(7384) $\"\"$ $\"About$

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what is the center (h,k) of 3x^2+12x+3y^2=0
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\n" ); document.write( "put in standard form of circle:
\n" ); document.write( "(x-h)^2 + (y-k)^2 = r^2
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\n" ); document.write( "3x^2+12x+3y^2=0
\n" ); document.write( "(3x^2+12x)+(3y^2)=0
\n" ); document.write( "3(x^2+4x) + 3(y^2)=0
\n" ); document.write( "3(x^2+4x+4) + 3(y^2)=12
\n" ); document.write( "3(x+2)^2 + 3(y^2) = 12
\n" ); document.write( "3(x-(-2))^2 + 3(y-0)^2 = 12
\n" ); document.write( "(x-(-2))^2 + (y-0)^2 = 4
\n" ); document.write( "center: (h,k) = (-2,0)
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