document.write( "Question 628750: A 150-lb person who runs at 6mph for 1hr burns about 720 calories. The same person, walking at 2 mph for 90 min, burns about 120 calories. Suppose a 150-lb person runs at 6 mph for 75 min. How far would the person have to walk at 2 mph in order to burn the same numberof calories as burned when running? \n" ); document.write( "
Algebra.Com's Answer #395819 by graphmatics(170)\"\" \"About 
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Let x be the number of calories generated per pound.\n" ); document.write( "let y be the calories generated per minute of speed. Then\n" ); document.write( "150x+6*60y=720\n" ); document.write( "150x+2*90y=120
\n" ); document.write( "150x+360y=720\n" ); document.write( "150x+180y=120\n" ); document.write( "we solve this system of equations\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
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\n" ); document.write( " Any system of equations:
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\n" ); document.write( " (x=-3.2, y=3.33333333333333}
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\n" ); document.write( "So x=3.2 and y=3.333333.\n" ); document.write( "For a 150 pound person running at 6 mph for 75 minutes the number of calories generated is\n" ); document.write( "150*3.2+6*75*3.333333=1978.5\n" ); document.write( "To find the distance covered at 2 mph we need to find the number of minutes required to generate 1978.5 calories so if z is the number of minutes\n" ); document.write( "150*3.2+2*z*3.333333=1978.5.
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