document.write( "Question 628737: Find the exact solution:\r
\n" ); document.write( "\n" ); document.write( "log(x+3)=1-log(x)
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Algebra.Com's Answer #395818 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
Find the exact solution:\r
\n" ); document.write( "\n" ); document.write( "log(x+3)=1-log(x)\r
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\n" ); document.write( "\n" ); document.write( "log (x + 3) = 1 – log x
\n" ); document.write( "log (x + 3) + log x = 1
\n" ); document.write( "log x(x + 3) = 1\r
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\n" ); document.write( "\n" ); document.write( "\"10%5E1+=+x%28x+%2B+3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+3x+-+10+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "(x + 5)(x – 2) = 0\r
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\n" ); document.write( "\n" ); document.write( "x = - 5 (ignore), or \"highlight_green%28x+=+2%29\" (accept)\r
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\n" ); document.write( "Check
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\n" ); document.write( "\n" ); document.write( "log (2 + 3) = 1 – log 2
\n" ); document.write( "log 5 = 1 – log 2
\n" ); document.write( "0.69897 = 1 - 0.30103
\n" ); document.write( "0.69897 = 0.69897 (TRUE) \r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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