document.write( "Question 628664: Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had traveled 4 mph faster, she could have made the trip in 1/2 hr less time. How far apart are the towns? \n" ); document.write( "
Algebra.Com's Answer #395815 by MathTherapy(10555)\"\" \"About 
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\n" ); document.write( "Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had traveled 4 mph faster, she could have made the trip in 1/2 hr less time. How far apart are the towns?\r
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\n" ); document.write( "\n" ); document.write( "Let distance between the towns be D\r
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\n" ); document.write( "\n" ); document.write( "Then: \"D%2F32+-+D%2F%2832+%2B+4%29+=+1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"D%2F32+-+D%2F36+=+1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "9D – 8D = 144 ----- Multiplying by LCD, 288\r
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\n" ); document.write( "\n" ); document.write( "D, or distance between the towns = \"highlight_green%28144%29\" miles\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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