document.write( "Question 628664: Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had traveled 4 mph faster, she could have made the trip in 1/2 hr less time. How far apart are the towns? \n" ); document.write( "
Algebra.Com's Answer #395815 by MathTherapy(10555)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had traveled 4 mph faster, she could have made the trip in 1/2 hr less time. How far apart are the towns?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let distance between the towns be D\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9D – 8D = 144 ----- Multiplying by LCD, 288\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D, or distance between the towns = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |