document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628727>Question 628727</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 2 sides of a tringle measure 32 and 19 cenimeters, and you have a multiple choice of the third side being 10,13,21, or 52 cenimeters. I know it can't be 52 because 19+32 is less than 52 but I'm stuck from there. Any suggestions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395800 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395800\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the similar logic with 10 and 13<BR>\n" );
document.write( "10+19 is less than 32<BR>\n" );
document.write( "13+19=32<BR>\n" );
document.write( "which leaves 21<BR>\n" );
document.write( " </SPAN>\n" );
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