document.write( "Question 628629: Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. Find the distance between P and Q.\r
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Algebra.Com's Answer #395795 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. Find the distance between P and Q.\r
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\n" ); document.write( "\n" ); document.write( "Let distance traveled by faster train be D
\n" ); document.write( "Then distance traveled by slower train = D - 100
\n" ); document.write( "Time taken by faster train to travel to meeting point = time taken by slower train to travel to the meeting point, OR
\n" ); document.write( "\"D%2F50+=+%28D+-+100%29%2F40\"\r
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\n" ); document.write( "\n" ); document.write( "50(D – 100) = 40D ------ Cross-multiplying\r
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\n" ); document.write( "\n" ); document.write( "50D – 5,000 = 40D\r
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\n" ); document.write( "\n" ); document.write( "50D - 40D = 5,000\r
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\n" ); document.write( "\n" ); document.write( "10D = 5,000
\n" ); document.write( "D, or distance traveled by faster train = \"5000%2F10\", or \"500\" km\r
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\n" ); document.write( "\n" ); document.write( "Distance traveled by slower train = 500 – 100, or \"400\" km\r
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\n" ); document.write( "\n" ); document.write( "Therefore, distance between P and Q = 500 + 400, or \"highlight_green%28900%29\" km\r
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\n" ); document.write( "\n" ); document.write( "You can do the check, I'm sure!!\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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