document.write( "Question 628662: solve the equation exactly over the interval [0,2pi)\r
\n" ); document.write( "\n" ); document.write( "cos 2x= sqrt2 -cos 2x
\n" ); document.write( "

Algebra.Com's Answer #395779 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
solve the equation exactly over the interval [0,2pi)
\n" ); document.write( "cos 2x= sqrt2 -cos 2x
\n" ); document.write( "------
\n" ); document.write( "2cos(2x) = sqrt(2)
\n" ); document.write( "cos(2x) = sqrt(2)/2
\n" ); document.write( "2x = pi/4 or -pi/4
\n" ); document.write( "x = pi/8 or -pi/8
\n" ); document.write( "==========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=============
\n" ); document.write( "
\n" );