document.write( "Question 628627: The ratio of the present ages of two brother is 1:2 and 5 years back the ratio was 1:3. What will be the ratio of their ages after 5 years?\r
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Algebra.Com's Answer #395754 by ankor@dixie-net.com(22740)\"\" \"About 
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The ratio of the present ages of two brother is 1:2
\n" ); document.write( " and 5 years back the ratio was 1:3.
\n" ); document.write( " What will be the ratio of their ages after 5 years?
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\n" ); document.write( "Two brothers ages a & b, now
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\n" ); document.write( "\"The ratio of the present ages of two brother is 1:2
\n" ); document.write( "\"a%2Fb\" = \"1%2F2\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "2a = b
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\n" ); document.write( "\"5 years back the ratio was 1:3.\"
\n" ); document.write( "\"%28a-5%29%2F%28b-5%29\" = \"1%2F3\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "3(a-5) = b - 5
\n" ); document.write( "3a - 15 = b - 5
\n" ); document.write( "3a = b - 5 + 15
\n" ); document.write( "3a = b + 10
\n" ); document.write( "Replace b with 2a
\n" ); document.write( "3a = 2a + 10
\n" ); document.write( "3a - 2a = 10
\n" ); document.write( "a = 10 yrs a's present age
\n" ); document.write( "then
\n" ); document.write( "2(20) = 20 yrs b's present age
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\n" ); document.write( "\"What will be the ratio of their ages after 5 years?\"
\n" ); document.write( "\"%2810%2B5%29%2F%2820%2B5%29\" = \"15%2F25\" = \"3%2F5\"; 3:5
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