document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628587>Question 628587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have all my homework done except for these last couple of questions and was hoping for some help. I really detest algebra.\r<BR>\n" );
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document.write( "1. |x|6\r<BR>\n" );
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document.write( "2. &#8730;20-8x=x\r<BR>\n" );
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document.write( "Thank in advance.\r<BR>\n" );
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document.write( "Rob </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395751 by </B><A HREF=/tutors/aboutme.mpl?userid=Logaritmo_94><B>Logaritmo_94(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Logaritmo_94><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. |x|= 6\r<BR>\n" );
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document.write( "x=+6 and x= -6. Because of the definition of abs.\r<BR>\n" );
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document.write( "2. (sqrt(20) - 8x)^2 = x^2 . Elevate both members to the power of 2. And apply the rule of the square of a binomial.\r<BR>\n" );
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document.write( "20 - 2. sqrt(20).8x + 16x^2 =x^2. Reduce terms and elevate to the power of 2, both members again...\r<BR>\n" );
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document.write( "(-16x sqrt (20))^2 = (-15x^2+20)^2 . Then do the same as below. And the solution of the equation are: array{ x=((2 sqrt(5))/(7)), &#8776;0.6388765649999}and array{ x=((2 sqrt(5))/(9)), &#8776;0.496903995}\r<BR>\n" );
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document.write( "    \r<BR>\n" );
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