document.write( "Question 628607: Please help me solve:
\n" );
document.write( "3/x+3 - 1/x^2-9=1/x-3 \n" );
document.write( "
Algebra.Com's Answer #395749 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! solve: \n" ); document.write( " \n" ); document.write( "the 2nd denominator is the difference of square and will factor: \n" ); document.write( " \n" ); document.write( "Multiply thru by (x-3)(x+3) and you have \n" ); document.write( "3(x-3) - 1 = x + 3 \n" ); document.write( "multiply what's inside the brackets \n" ); document.write( "3x - 9 - 1 = x + 3 \n" ); document.write( "3x - 10 = x + 3 \n" ); document.write( "3x - x = 3 + 10 \n" ); document.write( "2x = 13 \n" ); document.write( "x = 6.5 \n" ); document.write( " |