document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628571>Question 628571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x+y=40, then what is 2x equal to? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395742 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=40<BR>\n" );
document.write( "Multiply both sides by 2<BR>\n" );
document.write( "2(x+y)=(2)(40)<BR>\n" );
document.write( "2x+2y=80<BR>\n" );
document.write( "Subtract 2y from both sides<BR>\n" );
document.write( "2x+2y-2y=80-2y<BR>\n" );
document.write( "2x=80-2y </SPAN>\n" );
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