document.write( "Question 628513: The ages in the data set can be shown to be approximately normally distributed with a mean of 50 years and a standard deviation of 6 years. A person is randomly selected and their age observed. Find the probability that their age will fall between 55 and 60.
\n" ); document.write( "Now I got some of it: Z = (55-50/6) = (5/6) = 0.8333 = 0.2967 My question is where does 0.2967 come from?
\n" ); document.write( "How is that calculated from Z = (55-50/6) = (5/6) = 0.8333?
\n" ); document.write( "Please tell me how to enter it in my calculator. Thank you in advance. \n" ); document.write( "

Algebra.Com's Answer #395694 by John10(297) $\"\"$ $\"About$

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The ages in the data set can be shown to be approximately normally distributed with a mean of 50 years and a standard deviation of 6 years. A person is randomly selected and their age observed. Find the probability that their age will fall between 55 and 60. \r
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\n" ); document.write( "\n" ); document.write( "Find z-score of x = 55 and z = 60
\n" ); document.write( "z(55) = (55 - 50)/6 = 5/5 = 0.833
\n" ); document.write( "z(60) = (60 - 50)/6 = 10/6 = 1.67
\n" ); document.write( "Now we find the probability between 55 and 60:
\n" ); document.write( "P(55 < x < 60) = (0.83 < z < 1.67) = 0.156
\n" ); document.write( "Calculator: If you have TI-83 plus, you will press 2nd VARS the press \"2\" you will see \"normalcdf(0.83, 1.67)\".
\n" ); document.write( "Hope it helps:)
\n" ); document.write( "John10:) \n" ); document.write( "

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