document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628427>Question 628427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem.\r<BR>\n" );
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document.write( "The perimeter of a rectangle is found by using the formula: 2L + 2W. if the perimeter of a rectangle is 66 cm, and the length is twice the width, what is the length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395661 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395661\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is found by using the formula: 2L + 2W. <BR>\n" );
document.write( "if the perimeter of a rectangle is 66 cm, and the length is twice the width<BR>\n" );
document.write( "what is the length?\r<BR>\n" );
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document.write( "2L + 2W = 66:<BR>\n" );
document.write( "\"the length is twice the width\"; therefore<BR>\n" );
document.write( "L = 2W<BR>\n" );
document.write( "replace L with 2W<BR>\n" );
document.write( "2(2W) + 2W = 66<BR>\n" );
document.write( "4W + 2W = 66<BR>\n" );
document.write( "6W = 66<BR>\n" );
document.write( "W = 66/6<BR>\n" );
document.write( "W = 11 cm<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "2(11) = 22 cm is the length </SPAN>\n" );
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