document.write( "Question 628409: Hi, I need help with this logarithm:
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document.write( "log base 2 of (x) + log base 2 of (x+2)=log base 2 of (x+6)\r
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document.write( "I have attempted this equation but I keep coming to the solution of x=(x+6)/(x+2) and I don't know how to solve for x.\r
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document.write( "Please and thank you :) \n" );
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Algebra.Com's Answer #395607 by John10(297)![]() ![]() You can put this solution on YOUR website! log base 2 of (x) + log base 2 of (x+2)=log base 2 of (x+6) \r \n" ); document.write( "\n" ); document.write( "So we will have:\r \n" ); document.write( "\n" ); document.write( "log base 2 of [x(x+2)] = log base 2 of (x + 6) \n" ); document.write( "x(x +2) = x + 6 \n" ); document.write( "x^2 + 2x = x + 6 \n" ); document.write( "x^2 + x - 6= 0 \n" ); document.write( "(x +3)(x - 2) = 0 \n" ); document.write( "x = -3 or x = 2 \n" ); document.write( "We can NOT choose x = -3 because property of log x which x can not be negative. \n" ); document.write( "Thus the ONLY solution is x = 2. \n" ); document.write( "Hope it helps:) \n" ); document.write( "John10 \n" ); document.write( " |