document.write( "Question 628409: Hi, I need help with this logarithm:
\n" ); document.write( "log base 2 of (x) + log base 2 of (x+2)=log base 2 of (x+6)\r
\n" ); document.write( "\n" ); document.write( "I have attempted this equation but I keep coming to the solution of x=(x+6)/(x+2) and I don't know how to solve for x.\r
\n" ); document.write( "\n" ); document.write( "Please and thank you :)
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Algebra.Com's Answer #395607 by John10(297)\"\" \"About 
You can put this solution on YOUR website!
log base 2 of (x) + log base 2 of (x+2)=log base 2 of (x+6) \r
\n" ); document.write( "\n" ); document.write( "So we will have:\r
\n" ); document.write( "\n" ); document.write( "log base 2 of [x(x+2)] = log base 2 of (x + 6)
\n" ); document.write( "x(x +2) = x + 6
\n" ); document.write( "x^2 + 2x = x + 6
\n" ); document.write( "x^2 + x - 6= 0
\n" ); document.write( "(x +3)(x - 2) = 0
\n" ); document.write( "x = -3 or x = 2
\n" ); document.write( "We can NOT choose x = -3 because property of log x which x can not be negative.
\n" ); document.write( "Thus the ONLY solution is x = 2.
\n" ); document.write( "Hope it helps:)
\n" ); document.write( "John10
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