document.write( "Question 7165: Please help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( " \"+x%5E2-4x-9%2B0+\"
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Algebra.Com's Answer #3956 by prabhjyot(165)\"\" \"About 
You can put this solution on YOUR website!
\"+x%5E2-4x-9=0+\"
\n" ); document.write( "The above equation is in the form of \"AX%5E2+%2B+BX+%2B+C+=+0\"\r
\n" ); document.write( "\n" ); document.write( "where A=1,B= -4 , c= -9\r
\n" ); document.write( "\n" ); document.write( "Roots of the quadratic equation is found by
\n" ); document.write( "\"x=+-b+%2B-+sqrt%28b%5E2+-4ac+%29+%2F2a+\"\r
\n" ); document.write( "\n" ); document.write( "Substututing the values of A,B, in the formula above\r
\n" ); document.write( "\n" ); document.write( "\"x+=+4+%2B-+sqrt+%28%28-4%29%5E2+-++4+%2A1%2A+-9%29%2F2\"
\n" ); document.write( "\"+x=+4%2B-+sqrt%28+16+%2B36%29%2F2\"
\n" ); document.write( "\"+x=+4%2B-+sqrt%2852%29%2F2\"
\n" ); document.write( "solving we get
\n" ); document.write( "x1= 5.6056
\n" ); document.write( "x2= -1.6056
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