document.write( "Question 628314: 1500 is divided into three parts , 1/2 of the first part is same as 1/3rd of the second and 3/5th of third. find each part
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Algebra.Com's Answer #395575 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1500 is divided into three parts, 1/2 of the first part is same \n" ); document.write( " as 1/3rd of the second and \n" ); document.write( " 3/5th of third. \n" ); document.write( " find each part \n" ); document.write( ": \n" ); document.write( "\"1500 is divided into three parts,\" \n" ); document.write( "a + b + c = 1500 \n" ); document.write( ": \n" ); document.write( "\"1/2 of the first part is same as 1/3rd of the second\" \n" ); document.write( " \n" ); document.write( "multiply by 3 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "\"and 3/5th of third. find each part\" \n" ); document.write( " \n" ); document.write( "multiply by (5/3) \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "replace b and c in the total equation \n" ); document.write( "a + \n" ); document.write( "multiply by 6, results \n" ); document.write( "6a + 3(3a) + 5a = 6(1500) \n" ); document.write( "6a + 9a + 5a = 9000 \n" ); document.write( "20a = 9000 \n" ); document.write( "a = 9000/20 \n" ); document.write( "a = 450 is the 1st part \n" ); document.write( "then \n" ); document.write( "b = \n" ); document.write( "b = 675 is the 2nd part \n" ); document.write( "and \n" ); document.write( "c = \n" ); document.write( "c = 375 is the 3rd part \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that adds up: 450 + 675 + 375 = 1500 \n" ); document.write( " |