document.write( "Question 628314: 1500 is divided into three parts , 1/2 of the first part is same as 1/3rd of the second and 3/5th of third. find each part
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Algebra.Com's Answer #395575 by ankor@dixie-net.com(22740)\"\" \"About 
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1500 is divided into three parts, 1/2 of the first part is same
\n" ); document.write( " as 1/3rd of the second and
\n" ); document.write( " 3/5th of third.
\n" ); document.write( " find each part
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\n" ); document.write( "\"1500 is divided into three parts,\"
\n" ); document.write( "a + b + c = 1500
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\n" ); document.write( "\"1/2 of the first part is same as 1/3rd of the second\"
\n" ); document.write( "\"1%2F2\"a = \"1%2F3\"b
\n" ); document.write( "multiply by 3
\n" ); document.write( "\"3%2F2\"a = b
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\n" ); document.write( "\"and 3/5th of third. find each part\"
\n" ); document.write( "\"1%2F2\"a = \"3%2F5\"c
\n" ); document.write( "multiply by (5/3)
\n" ); document.write( "\"5%2F6\"a = c
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\n" ); document.write( "replace b and c in the total equation
\n" ); document.write( "a + \"3%2F2\"a + \"5%2F6\"a = 1500
\n" ); document.write( "multiply by 6, results
\n" ); document.write( "6a + 3(3a) + 5a = 6(1500)
\n" ); document.write( "6a + 9a + 5a = 9000
\n" ); document.write( "20a = 9000
\n" ); document.write( "a = 9000/20
\n" ); document.write( "a = 450 is the 1st part
\n" ); document.write( "then
\n" ); document.write( "b = \"3%2F2\"*450
\n" ); document.write( "b = 675 is the 2nd part
\n" ); document.write( "and
\n" ); document.write( "c = \"5%2F6\"*450
\n" ); document.write( "c = 375 is the 3rd part
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\n" ); document.write( "See if that adds up: 450 + 675 + 375 = 1500
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