document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628361>Question 628361</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given an isosceles right triangle with sides length 5 cm, solve for the hypotenuse </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395572 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395572\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We know that the isosceles right triangle has two equal sides and a 90 degree angle between them. And we know that each side is equal to 5. so we will find the hypotenuse side by the Pythagorean Theorem.\r<BR>\n" );
document.write( "\n" );
document.write( "Hint: Draw a picture will be better to see.\r<BR>\n" );
document.write( "\n" );
document.write( "Pythagorean theorem: h^2 = a^2 + b^2 = 5^2 + 5^2 = 25 + 25 = 50 so h = sqrt(50) or h = 5sqrt(2)\r<BR>\n" );
document.write( "\n" );
document.write( "Hope it helps:)<BR>\n" );
document.write( "John10<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );