document.write( "Question 628312: An automobile car traveled 200 miles and at same time a track can travel 150 miles .If the automobile travels at the average speed of 15 miles per hour faster than the track then . Find their average rate? \n" ); document.write( "
Algebra.Com's Answer #395565 by ankor@dixie-net.com(22740)\"\" \"About 
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An automobile car traveled 200 miles and at same time
\n" ); document.write( "a truck can travel 150 miles .
\n" ); document.write( "If the automobile travels at the average speed of 15 miles per hour faster
\n" ); document.write( " than the truck then .
\n" ); document.write( "Find their average rate?
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\n" ); document.write( "Let s = speed of the truck
\n" ); document.write( "then
\n" ); document.write( "(s+15) = speed of the car
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\n" ); document.write( "Write a time equation: time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "truck time = car time
\n" ); document.write( "\"150%2Fs\" = \"200%2F%28%28s%2B15%29%29\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "150(s+15) = 200s
\n" ); document.write( "150s = 2250 = 200s
\n" ); document.write( "2250 = 200s - 150s
\n" ); document.write( "2250 = 50s
\n" ); document.write( "s = 2250/50
\n" ); document.write( "s = 45 mph is the speed of the truck
\n" ); document.write( "then
\n" ); document.write( "45 + 15 = 60 mph is the speed of the car
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the time of each, they should be equal
\n" ); document.write( "150/45 = 3.33 hrs
\n" ); document.write( "200/60 = 3.33 hrs
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