document.write( "Question 628312: An automobile car traveled 200 miles and at same time a track can travel 150 miles .If the automobile travels at the average speed of 15 miles per hour faster than the track then . Find their average rate? \n" ); document.write( "
Algebra.Com's Answer #395565 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An automobile car traveled 200 miles and at same time \n" ); document.write( "a truck can travel 150 miles . \n" ); document.write( "If the automobile travels at the average speed of 15 miles per hour faster \n" ); document.write( " than the truck then . \n" ); document.write( "Find their average rate? \n" ); document.write( ": \n" ); document.write( "Let s = speed of the truck \n" ); document.write( "then \n" ); document.write( "(s+15) = speed of the car \n" ); document.write( "; \n" ); document.write( "Write a time equation: time = dist/speed \n" ); document.write( ": \n" ); document.write( "truck time = car time \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "150(s+15) = 200s \n" ); document.write( "150s = 2250 = 200s \n" ); document.write( "2250 = 200s - 150s \n" ); document.write( "2250 = 50s \n" ); document.write( "s = 2250/50 \n" ); document.write( "s = 45 mph is the speed of the truck \n" ); document.write( "then \n" ); document.write( "45 + 15 = 60 mph is the speed of the car \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding the time of each, they should be equal \n" ); document.write( "150/45 = 3.33 hrs \n" ); document.write( "200/60 = 3.33 hrs \n" ); document.write( " |