document.write( "Question 628299: Frank and Page are on opposing football teams. Frank gets the ball at his team's 20 yard line and runs for a touchdown. When Frank reaches his own 40 yd line, Page runs after him from Frank's 20 yard line. Frank runs 7 yd/second, and Page runs 8 yd/second. Will Page catch up before he secures the touchdown? If so, on which yard? \r
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Algebra.Com's Answer #395541 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+d+\" = the distance in yds that Frank runs
\n" ); document.write( "until he gets caught by Page
\n" ); document.write( "Frank's equation is
\n" ); document.write( "(1) \"+d+=+7t+\" where \"d\" is in yds and \"t\" is in sec
\n" ); document.write( "Page's equation:
\n" ); document.write( "(2) \"+d+%2B+20+=+8t+\"
\n" ); document.write( "Note that Page has to run 20 yds further and time
\n" ); document.write( "spent running is the same for both
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\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+7t+%2B+20+=+8t+\"
\n" ); document.write( "(2) \"+t+=+20+\" sec
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\n" ); document.write( "Now plug this back into (1) or (2)
\n" ); document.write( "(1) \"+d+=+7%2A20+\"
\n" ); document.write( "(1) \"+d+=+140+\"
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\n" ); document.write( "What this says is that Frank won't get caught until
\n" ); document.write( "he has run 140 yds. But he only needs to run 60
\n" ); document.write( "yds to get a TD. So Page can't stop him from scoring.\r
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