document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628267>Question 628267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tommy is twice as old as Billy. If in two years the sum of their age is 79. How old is Tommy and Billy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395499 by </B><A HREF=/tutors/aboutme.mpl?userid=MrLarame><B>MrLarame(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MrLarame><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If Tommy is twice as old as Billy, then we can use variables to represent their ages like this:<BR>\n" );
document.write( "B = Billy's Age<BR>\n" );
document.write( "B * 2  = Tommy's Age\r<BR>\n" );
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document.write( "Then, if their two ages add up to be 2 years less than 79, we can write the whole question in \"math language\" as:<BR>\n" );
document.write( "B + B*2 = 79 - 2\r<BR>\n" );
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document.write( "Now we simplify, since 1B added to 2B's is 3B's, we get:<BR>\n" );
document.write( "3B = 77\r<BR>\n" );
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document.write( "If 3 B's is 77, then 1 B would be 1/3 of 77, or 77/3.\r<BR>\n" );
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document.write( "B (Billy's age) is 25 2/3 or 25 years and 8 mos.<BR>\n" );
document.write( "Since Tommy is twice that old, his age is 50 years and 16 months or 51 years and 4 mos. </SPAN>\n" );
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