document.write( "Question 628135: I have some equations in the following format (finding the nth term of an algebraic expression)\r
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document.write( "( n ) a^(n-(r-1)) * b^(r-1)
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document.write( " r-1\r
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document.write( "I don't understand what the (n & r-1) terms in the parenthesis at the beginning of the expression are. From the solution, it suggests that the first term ends up resolving to a division of factorials such as:\r
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document.write( "(6! / ((6-3)! * 3!)) where n=6 and r=4...\r
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document.write( "I just dont understand how they got from the first form to the factorial form. \n" );
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Algebra.Com's Answer #395467 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I think what you are looking at is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In general, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's the logic: Let's say you have 6 things and want to choose 3 of them. There are 6 ways to choose the first one, then since you didn't replace the first one you chose, there are 5 ways to choose the second one for each one of the 6 ways to choose the first one. Then there are 4 ways to choose the third one for each of the 30 ways to pick the first two, which works out to \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You might want to compare this to the number of permutations of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "By the way, this is also the \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |