document.write( "Question 628207: How do I factor a radicand to the perfect fourth power? I have the problem. 4√486x^12y^14. I know that it becomes 4√81*6*x^12y^14 and the answer is 3x^3y^34√6y^2. I am having trouble understanding how 486 became 81 and then 3x. your help would be greatly appreciated. \n" ); document.write( "

Algebra.Com's Answer #395462 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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the problem. $\"4sqrt%28486x%5E12y%5E14%29\"$
\n" ); document.write( "factor in a manner that will will reveal the perfect 4th power values
\n" ); document.write( "4th power of 3 is 81 and is also a factor of 486, going into that 6 times
\n" ); document.write( ":
\n" ); document.write( " $\"4sqrt%2881%2A6%2Ax%5E4%2Ax%5E4%2Ax%5E4%2Ay%5E4%2Ay%5E4%2Ay%5E2%29\"$
\n" ); document.write( "extract the 4th root of the perfect 4ths and you have
\n" ); document.write( "3*x*x*x*y*y* $\"4sqrt%286y%5E2%29\"$
\n" ); document.write( "which is
\n" ); document.write( " $\"3x%5E3%2Ay%5E2\"$ $\"4sqrt%286y%5E2%29\"$ \n" ); document.write( "

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