document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628152>Question 628152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The present age of the father is 3 years more than 3 times the age of the son,3years after father age will be 10 years more than twice the age of the son.find the age of father and son?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395420 by </B><A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><B>dfrazzetto(283)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dfrazzetto><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Current ages:\r<BR>\n" );
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document.write( "F = 3 + 3S\r<BR>\n" );
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document.write( "In 3 years time:\r<BR>\n" );
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document.write( "F + 3 = 10 + 2(S+3)\r<BR>\n" );
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document.write( "Solving by substitution:\r<BR>\n" );
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document.write( "3 + 3S + 3 = 10 + 2(S+3)\r<BR>\n" );
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document.write( "6 + 3S = 10 + 2S + 6\r<BR>\n" );
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document.write( "S = 10\r<BR>\n" );
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document.write( "F = 33 </SPAN>\n" );
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