document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57773>Question 57773</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Y=2/3x and Y=-2/7x+4/7\r<BR>\n" );
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document.write( "I am not even sure how to set this up.  Do I need to have the y-intercept for the first system of equation befor I can solve?  Can you please help me set this problem up?  Thanks for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39542 by </B><A HREF=/tutors/aboutme.mpl?userid=phillv><B>phillv(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=phillv><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You do not need the Y intercept.<BR>\n" );
document.write( "Just substitute 2/3x for Y in the second equation.<BR>\n" );
document.write( "This gives us 2/3x=-2/7x+4/7<BR>\n" );
document.write( "2/3x=(4-2x)/7<BR>\n" );
document.write( "multiply both sides by 7<BR>\n" );
document.write( "14/3x=4-2x<BR>\n" );
document.write( "multiply both sides by 3<BR>\n" );
document.write( "14x=12-6x<BR>\n" );
document.write( "simplify<BR>\n" );
document.write( "20x=12<BR>\n" );
document.write( "x=12/20=3/5<BR>\n" );
document.write( "x=3/5<BR>\n" );
document.write( "substitute 3/5 for x in either of the original equations<BR>\n" );
document.write( "Y=(2/3)(3/5)<BR>\n" );
document.write( "Y=2/5<BR>\n" );
document.write( "X=3/5 and Y=2/5 will satisfy both equations. </SPAN>\n" );
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