document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628144>Question 628144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in pentagon MTLYN m angle m=90 and M angle T=150 m angle Y and m angle N are each twice as large as m angle L find the measures of angle L angle Y and angle N </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395419 by </B><A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><B>dfrazzetto(283)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dfrazzetto><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sum of  interior angles (in degrees) of a polygon:\r<BR>\n" );
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document.write( "n = sides\r<BR>\n" );
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document.write( "&#931;(sum) = (n-2)180 = 3(180) = 540\r<BR>\n" );
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document.write( "M = 90\r<BR>\n" );
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document.write( "T = 150\r<BR>\n" );
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document.write( "Y = N = 2L\r<BR>\n" );
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document.write( "M + T + Y + N + L = 540\r<BR>\n" );
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document.write( "90 + 150 + 2L + 2L + L = 540\r<BR>\n" );
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document.write( "5L = 540 - 90 - 150\r<BR>\n" );
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document.write( "5L = 300\r<BR>\n" );
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document.write( "L = 60\r<BR>\n" );
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document.write( "Y = N = 2L = 120\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "90 + 150 + 120 + 120 + 60 = 540 </SPAN>\n" );
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