document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628139>Question 628139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the ages of a and b is 45 years.after 10 years a age is twise that of b age.find a age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395411 by </B><A HREF=/tutors/aboutme.mpl?userid=Susmitha><B>Susmitha(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Susmitha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Susmitha><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> given sum of the ages of a and b is 45<BR>\n" );
document.write( "so, a+b=45<BR>\n" );
document.write( "then given after ten years a age is twice that of b<BR>\n" );
document.write( "so, a=2b<BR>\n" );
document.write( "2b+b=45<BR>\n" );
document.write( "3b=45<BR>\n" );
document.write( "b=45/3<BR>\n" );
document.write( "b=15<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "a+ 15=45<BR>\n" );
document.write( "a=45-15<BR>\n" );
document.write( "a=30<BR>\n" );
document.write( "-------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );