document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57861>Question 57861</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0495012661/algebrahomeworkh>college algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A Truck that cost $27,600 when new will have no salvage value after 12 years.  Find the annual rate of depeciation.\r<BR>\n" );
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document.write( "Can anyone give me a hand with this one?  Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39538 by </B><A HREF=/tutors/aboutme.mpl?userid=rcmcc><B>rcmcc(152)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rcmcc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rcmcc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this equation can be calculated the same way we calculate simple interest. \r<BR>\n" );
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document.write( "use the equation a=p+prt\r<BR>\n" );
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document.write( "where p is the principle amount r is the rate of decrease and t is the time in years. and A is 0\r<BR>\n" );
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document.write( "substitute the values in for the equation\r<BR>\n" );
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document.write( "0=27600+(27600)(r)(12)\r<BR>\n" );
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document.write( "subtract 27600 from each side\r<BR>\n" );
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document.write( "-27600=(27600)(r)(12)\r<BR>\n" );
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document.write( "divide both sides by (27600)(12) to isolate r<BR>\n" );
document.write( "-27600/(27600)(12)=r\r<BR>\n" );
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document.write( "r=-0.08333333\r<BR>\n" );
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document.write( "or r is 8.33333333% decrease per year </SPAN>\n" );
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