document.write( "Question 628095: The sum of twice a number and 1 is equal to 3 times the positive square root of the number. Find the number. Write an equation and solve. \n" ); document.write( "
Algebra.Com's Answer #395379 by mananth(16946)\"\" \"About 
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The sum of twice a number and 1 is equal to 3 times the positive square root of the number. Find the number. Write an equation and solve.\r
\n" ); document.write( "\n" ); document.write( "Let the number be x\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B1+=+3sqrt%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "square both sides\r
\n" ); document.write( "\n" ); document.write( "\"%282x%2B1%29%5E2+=+%283sqrt%28x%29%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"4x%5E2%2B4x%2B1=+9x\"\r
\n" ); document.write( "\n" ); document.write( "\"4x%5E2-5x%2B1=0\"\r
\n" ); document.write( "\n" ); document.write( "\"4x%5E2-4x-x%2B1=0\"\r
\n" ); document.write( "\n" ); document.write( "\"4x%28x-1%29%2B1%28x-1%29=0\"\r
\n" ); document.write( "\n" ); document.write( "(x-1)(4x-1)=0\r
\n" ); document.write( "\n" ); document.write( "either x-1 = 0 or 4x-1 =0\r
\n" ); document.write( "\n" ); document.write( "if x-1 =0
\n" ); document.write( "x= 1
\n" ); document.write( "if 4x-1 =0 then
\n" ); document.write( "4x=1
\n" ); document.write( "x= 1/4\r
\n" ); document.write( "\n" ); document.write( "x= 1OR 1/4\r
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