document.write( "Question 628081: x+ 5x-2/9-7=3x+4/3 \n" ); document.write( "
Algebra.Com's Answer #395376 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I think I answered this before (or already). If not, then here it is again.\r
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\n" ); document.write( "\n" ); document.write( "Multiply everything by the LCD 9 to clear out the fractions to get
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\n" ); document.write( "9x + 9(5x-2)/9 - 7*9 = 9(3x+4)/3
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\n" ); document.write( "9x + 1(5x-2) - 63 = 3(3x+4)
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\n" ); document.write( "Now solve for x
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\n" ); document.write( "9x + 1(5x-2) - 63 = 3(3x+4)
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\n" ); document.write( "9x + 1(5x)+1(-2) - 63 = 3(3x)+3(4)
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\n" ); document.write( "9x + 5x - 2 - 63= 9x + 12
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\n" ); document.write( "14x - 65 = 9x + 12
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\n" ); document.write( "14x - 65 - 9x = 12
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\n" ); document.write( "14x - 9x = 12 + 65
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\n" ); document.write( "5x = 77
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\n" ); document.write( "x = 77/5
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\n" ); document.write( "So the solution is x = 77/5\r
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\n" ); document.write( "\n" ); document.write( "Feel free to ask any questions you have. Thanks.
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