document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628008>Question 628008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use algebraic procedures to find the exact solution(s) of the equation. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.)<BR>\n" );
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document.write( "e^(x + 3) = 22 \r<BR>\n" );
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document.write( "x=? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395354 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> e^(x + 3) = 22 <BR>\n" );
document.write( "Find the nat log of each side<BR>\n" );
document.write( "ln(e^x+3)) = ln(22)<BR>\n" );
document.write( "log equiv of exponents<BR>\n" );
document.write( "(x+3)ln(e) = ln(22)<BR>\n" );
document.write( "Find the log, ln of e is 1 so we have<BR>\n" );
document.write( "x + 3 = 3.09104<BR>\n" );
document.write( "x = 3.09104 - 3<BR>\n" );
document.write( "x = .09104<BR>\n" );
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document.write( "Check this on you calc<BR>\n" );
document.write( "enter e^(.09104+3) results: 21.99999 ~ 22 </SPAN>\n" );
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