document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=627946>Question 627946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3(4y-1)=16y+5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395230 by </B><A HREF=/tutors/aboutme.mpl?userid=Cosx><B>Cosx(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cosx><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You do a distributive to the first member of the equation: 12y-3=16y+5, so you put the \"xs\" in one member and the independient terms in the other, so: 4y=8, dividing each members by 4, you have the result: y=2 </SPAN>\n" );
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