document.write( "Question 57840: C= nE/(R+nr)\r
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document.write( "You are supposed to find n. \r
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document.write( "Thanks, Danielle \n" );
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Algebra.Com's Answer #39523 by phillv(13)![]() ![]() ![]() You can put this solution on YOUR website! C=nE/(R+nr) \n" ); document.write( "Start by getting rid of the denominator and multiplying both sides of the equation by (R+nr) ie C(R+nr)= (nE(R+nr))/(R+nr) \n" ); document.write( "cancell out the (R+nr) in both the numerator and denominator on the right side of the equation. \n" ); document.write( "This leaves C(R+nr)=nE \n" ); document.write( "now expand the expression on the left side in order to isolate terms involving n on the left side. \n" ); document.write( "CR+Cnr=nE \n" ); document.write( "Subtract Cnr from both sides of the equation in order to get all terms involving n on one side of the equation. \n" ); document.write( "CR+Cnr-Cnr=nE-Cnr \n" ); document.write( "CR=nE-Cnr \n" ); document.write( "now factor out n from the right side of the equation \n" ); document.write( "CR=n(E-Cr) \n" ); document.write( "divide both sides of the equation by (E-Cr) in order to isolate n on one side of the equation. \n" ); document.write( "CR/(E-Cr)=n(E-Cr)/(E-Cr) \n" ); document.write( "cancell out (E-Cr) in the denominator and numerator on the right side. \n" ); document.write( "this leaves CR/(E-Cr)=n or n=CR/(E-Cr) \n" ); document.write( " |