document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=627839>Question 627839</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Makana invested $700 in a simple interest account that had an interest rate that was 1% more than that of her friend Marlys. If Marlys earned $39 after one year from an investment of $650, how much would Makana earn in 1 year? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #395178 by </B><A HREF=/tutors/aboutme.mpl?userid=reviewermath><B>reviewermath(1029)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=reviewermath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=reviewermath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=395178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Marlys investment's interest rate: 39/650 = 6%<BR>\n" );
document.write( "Therefore, Makana investment's interest rate = 6% + 1% = 7%<BR>\n" );
document.write( "Makana earns 0.07(700) = $49 in 1 year<BR>\n" );
document.write( "Answer: $49 </SPAN>\n" );
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