document.write( "Question 57824: construct a paralellogram ABCD in which BC=5.5cm, CD=2.5cm and angle ABC=60 degrees. Measure AC and BD \n" ); document.write( "
Algebra.Com's Answer #39514 by venugopalramana(3286)\"\" \"About 
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construct a paralellogram ABCD in which BC=5.5cm, CD=2.5cm and angle ABC=60 degrees. Measure AC and BD
\n" ); document.write( "IN A PARALELOGRAM OPPOSITE SIDES ARE EQUAL.
\n" ); document.write( "HENCE AB=CD=2.5....BC=DA=5.5
\n" ); document.write( "DRAW BC = 5.5.
\n" ); document.write( "WITH B AS CENTRE DRAW AN ARC OF RADIUS = AB = 2.5.
\n" ); document.write( "AT B DRAW A LINE BX MAKING ANGLE OF 60 DEGREES WITH BC..THAT IS ANGLE XBC=60
\n" ); document.write( "LET THE ARC CUT BX AT A.
\n" ); document.write( "WITH A AS CENTRE AND RADIUS EQUAL TO AD=5.5 DRAW AN ARC.
\n" ); document.write( "WITH C AS CENTRE AND RADIUS EQUAL TO CD=2.5 DRAW AN ARC.
\n" ); document.write( "LET THE 2 ARCS CUT AT D.
\n" ); document.write( "JOIN CD AND DA
\n" ); document.write( "ABCD IS THE REQUIRED PARALLELOGRAM.
\n" ); document.write( "AC^2=AB^2+BC^2-2*AB*BC*COS(60) = 22.75
\n" ); document.write( "AC=4.77=4.8
\n" ); document.write( "BD=AC^2+CB^2-2*AC*CB*COS(120)= 50.25
\n" ); document.write( "BD=7.09=7.1
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