document.write( "Question 627731: The centroid of triangle ABC is at point (6,0), the orthocentre at point(7,14/3),and the circumcentre at point (53/9, -7/3). They are collinear. what is the equation of the line passing through these points and how do i get there because my teacher has not taught us this but expects us to know. \n" ); document.write( "
Algebra.Com's Answer #395093 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Your three points are not collinear.\r
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\n" ); document.write( "\n" ); document.write( "However, you only need two points to define a line. In general, use the two-point form of an equation of a line:\r
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\n" ); document.write( "\n" ); document.write( "where and are the coordinates of the given points.\r
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\n" ); document.write( "\n" ); document.write( "Just plug in the numbers, do the arithmetic, and simplify.\r
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\n" ); document.write( "\n" ); document.write( "By the way, here is how I know that your three points are not collinear:\r
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\n" ); document.write( "\n" ); document.write( "If three points lie on the same line, then the slope of the segment between any of pair of them must be equal. Use the slope formula:\r
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\n" ); document.write( "\n" ); document.write( "where and are the coordinates of the given points.\r
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\n" ); document.write( "\n" ); document.write( "to calculate the slope between each of the three pairs of points (centroid/orthorcenter, orthocenter/circumcenter, and circumcenter/centroid), You will find that you get three different results, hence the three points are not collinear.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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