document.write( "Question 57794: Determine the domain and range of the function -x^2 + 6x - 8. \n" ); document.write( "
Algebra.Com's Answer #39507 by funmath(2933)\"\" \"About 
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Determine the domain and range of the function y=-x^2 + 6x - 8.
\n" ); document.write( "Domain has to do with what your x values are allowed to be. The domain of all polynomial functions is: all real numbers. There are no restrictions on what x can be.
\n" ); document.write( "Set builder notation for the domain would be: {x|x is all real numbers}
\n" ); document.write( "Interval notation would be: x=(-infinity,infinity) I can't do the infinity symbols yet.
\n" ); document.write( ":
\n" ); document.write( "Range has to do with what the y values are given that the function's domain is what it is.
\n" ); document.write( "For quadratic functions, the range is found through the vertex and whether the graph is opening up or down.
\n" ); document.write( "The coefficient of x^2 is negative, therefore our parabola opens downward and goes to negative infinity. It's vertex is at its maximum height. We can find the vertex with the formula: \"highlight%28x=-b%2F2a%29\", our a=-1, b=6 and c=-8
\n" ); document.write( "\"x=-%286%29%2F%282%28-1%29%29\"
\n" ); document.write( "\"x=-6%2F-2\"
\n" ); document.write( "\"x=3\"
\n" ); document.write( "The maximum y value will happen when x=3:
\n" ); document.write( "\"y=-1%283%29%5E2%2B6%283%29-8\"
\n" ); document.write( "\"y=-1%289%29%2B6%283%29-8\"
\n" ); document.write( "\"y=-9%2B18-8\"
\n" ); document.write( "\"y=1\"
\n" ); document.write( "Therefore the range is: - infinity to 1
\n" ); document.write( "(-infinity,1] <---- interval notation
\n" ); document.write( ":
\n" ); document.write( "If you don't have to do this algebraically and you can use a graphing calculator, then graph the equation:
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C-x%5E2%2B6x-8%29\"
\n" ); document.write( "The x's extend forever left and right, the y' go from 1 down to -infinity.
\n" ); document.write( "Happy Calculating!!!
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