document.write( "Question 627671: a woman is 4 times older than her daughter, 6 years ago the product of their ages was 136. find their present age \n" ); document.write( "
Algebra.Com's Answer #395057 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of woman = w years old
\n" ); document.write( "Present age of daughter = d years old\r
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\n" ); document.write( "\n" ); document.write( "woman is 4 times older than her daughter
\n" ); document.write( "w=4d............(1)
\n" ); document.write( "6 years ago
\n" ); document.write( "woman was = w-6 years old
\n" ); document.write( "daughter was = d-6
\n" ); document.write( "then
\n" ); document.write( "product of their ages was 136
\n" ); document.write( "(w-6)(d-6)=136
\n" ); document.write( "substitute the value of from (1) to above equation
\n" ); document.write( "(4d-6)(d-6)=136
\n" ); document.write( "4d^2-24d-6d+36=136
\n" ); document.write( "4d^2-30d+36=136
\n" ); document.write( "2(2d^2-15d+18)=136
\n" ); document.write( "Divide by 2 both sides
\n" ); document.write( "2(2d^2-15d+18)/2=136/2
\n" ); document.write( "2d^2-15d+18=68
\n" ); document.write( "2d^2-15d+18-68=0
\n" ); document.write( "2d^2-15d-50=0
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ad%5E2%2Bbd%2Bc=0\" (in our case \"2d%5E2%2B-15d%2B-50+=+0\") has the following solutons:
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\n" ); document.write( " \"d%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-15%29%5E2-4%2A2%2A-50=625\".
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\n" ); document.write( " Discriminant d=625 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--15%2B-sqrt%28+625+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"d%5B1%5D+=+%28-%28-15%29%2Bsqrt%28+625+%29%29%2F2%5C2+=+10\"
\n" ); document.write( " \"d%5B2%5D+=+%28-%28-15%29-sqrt%28+625+%29%29%2F2%5C2+=+-2.5\"
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\n" ); document.write( " Quadratic expression \"2d%5E2%2B-15d%2B-50\" can be factored:
\n" ); document.write( " \"2d%5E2%2B-15d%2B-50+=+2%28d-10%29%2A%28d--2.5%29\"
\n" ); document.write( " Again, the answer is: 10, -2.5.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-15%2Ax%2B-50+%29\"

\n" ); document.write( "\n" ); document.write( "d=10 or d=-2.5 (unacceptable)
\n" ); document.write( "so
\n" ); document.write( "d=10
\n" ); document.write( "Put the value of d in (1)
\n" ); document.write( "w=4d
\n" ); document.write( "w=4(10)
\n" ); document.write( "w=40\r
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\n" ); document.write( "\n" ); document.write( "Present age of woman = w = 40 years old
\n" ); document.write( "Present age of daughter = d = 10 years old
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