document.write( "Question 627527: three years ago, marc's age was 1 year more than thrice aaron's 4 years from now marc's age will be 2 years more than twice aaron's. How old is Marc?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #394977 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! ): three years ago, marc's age was 1 year more than thrice aaron's \n" ); document.write( "m-3 = 3(a-3) + 1 \n" ); document.write( "m - 3 = 3a - 9 + 1 \n" ); document.write( "m = 3a - 8 + 3 \n" ); document.write( "m = 3a -5 \n" ); document.write( ": \n" ); document.write( "4 years from now marc's age will be 2 years more than twice aaron's. \n" ); document.write( "m + 4 = 2(a+4) + 2 \n" ); document.write( "m + 4 = 2a + 8 + 2 \n" ); document.write( "m = 2a + 10 -4 \n" ); document.write( "m = 2a + 6 \n" ); document.write( "Replace m with (3a-5) \n" ); document.write( "3a - 5 = 2a + 6 \n" ); document.write( "3a - 2a = 6 + 5 \n" ); document.write( "a = 11 yrs is Aaron's age \n" ); document.write( ": \n" ); document.write( "How old is Marc? \n" ); document.write( "m = 3(11) - 5 \n" ); document.write( "m = 33 - 5 \n" ); document.write( "m = 28 yrs \n" ); document.write( ": \n" ); document.write( "Check solutions in the 2nd statement \n" ); document.write( " \n" ); document.write( " |