document.write( "Question 627522: convert to equation: Jane walks 1 mile to the book store in the same time she can bicycle 2.5 miles to the mall. The speed on the bicycle is 6 miles/hour faster than her walking speed. What is her walking speed? \n" ); document.write( "
Algebra.Com's Answer #394967 by ankor@dixie-net.com(22740)\"\" \"About 
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Jane walks 1 mile to the book store in the same time she can bicycle 2.5 miles to the mall.
\n" ); document.write( " The speed on the bicycle is 6 miles/hour faster than her walking speed.
\n" ); document.write( " What is her walking speed?
\n" ); document.write( ":
\n" ); document.write( "Let w = the walking speed
\n" ); document.write( "then
\n" ); document.write( "(w+6) = the biking speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "walk time = bike time
\n" ); document.write( "\"1%2Fw\" = \"2.5%2F%28%28w%2B6%29%29\"
\n" ); document.write( "cross multiply
\n" ); document.write( "2.5w = 1(w+6)
\n" ); document.write( "2.5w = w + 6
\n" ); document.write( "2.5w - w = 6
\n" ); document.write( "1.5w = 6
\n" ); document.write( "w = \"6%2F1.5\"
\n" ); document.write( "w = 4 mph is the walking speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "We can check this by finding the times of each, should be equal
\n" ); document.write( "walk: 1/4 hr
\n" ); document.write( "bike: 10/2.5 = 1/4 hr \n" ); document.write( "
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