document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=627528>Question 627528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice its width. When the length is increased by five and the width is decreased by three, the new rectangle will have a perimeter of 52. Find the dimensions of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #394958 by </B><A HREF=/tutors/aboutme.mpl?userid=reviewermath><B>reviewermath(1029)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=reviewermath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=reviewermath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=394958\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = width<BR>\n" );
document.write( " so 2x = length\r<BR>\n" );
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document.write( "2x + 5 = new length<BR>\n" );
document.write( "x - 3 = new width<BR>\n" );
document.write( "Perimeter = 2(2x + 5) + 2(x - 3) = 52, divide both sides by 2.<BR>\n" );
document.write( "              (2x + 5) + (x - 3) = 26<BR>\n" );
document.write( "              3x + 2 = 26<BR>\n" );
document.write( "              3x = 24<BR>\n" );
document.write( "               x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%288%29 ALIGN=MIDDLE  ALT=\"highlight%288%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the width of the original rectangle<BR>\n" );
document.write( "              2x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%2816%29 ALIGN=MIDDLE  ALT=\"highlight%2816%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the length of the original rectangle </SPAN>\n" );
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