document.write( "Question 627499: The perimeter of a rectangular room is 120 feet. The sum of four times the width and three times the length is 204 feet. Find the length and the width of the room.
\n" ); document.write( "I just can't figure out how I would go about solving this problem. I have tried a few different ways and it does not look like i know what I am doing. I know i got to do it as P=W+L. But thats as far as i get. P being 120 feet= 4W+3L
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Algebra.Com's Answer #394956 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You are mistaken about perimeter.
\n" ); document.write( "Remember that in a rectangle, there are:
\n" ); document.write( "2 long sides plus
\n" ); document.write( "2 short sides which gives me
\n" ); document.write( "4 sides total
\n" ); document.write( "So the formula for perimeter is
\n" ); document.write( "\"+P+=+2L+%2B+2W+\"
\n" ); document.write( "You are given \"+P+=+120+\" ft
\n" ); document.write( "\"+120+=+2L+%2B+2W+\"
\n" ); document.write( "Divide through by \"2\"
\n" ); document.write( "(1) \"+60+=+L+%2B+W+\"
\n" ); document.write( "also
\n" ); document.write( "(2) \"+4W+%2B+3L+=+204+\"
\n" ); document.write( "-------------------------
\n" ); document.write( "(1) \"+W+=+60+-+L+\"
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+4%2A%28+60+-+L+%29+%2B+3L+=+204+\"
\n" ); document.write( "(2) \"+240+-+4L+%2B+3L+=+204+\"
\n" ); document.write( "(2) \"+-L+=+-36+\"
\n" ); document.write( "(2) \"+L+=+36+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+W+=+60+-+L+\"
\n" ); document.write( "(1) \"+W+=+60+-+36+\"
\n" ); document.write( "(1) \"+W+=+24+\"
\n" ); document.write( "The length is 36 ft
\n" ); document.write( "The width is 24 ft
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+4W+%2B+3L+=+204+\"
\n" ); document.write( "(2) \"+4%2A24+%2B+3%2A36+=+204+\"
\n" ); document.write( "(2) \"+96+%2B+108+=+204+\"
\n" ); document.write( "(2) \"+204+=+204+\"
\n" ); document.write( "OK
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