document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=627399>Question 627399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if i have 12' abs pipe want cut 3 pices one at 33 3/8 and seccon at 56 5/8 and tird at 39 7/8 the saw at 1/8 what got left<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #394926 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=394926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if i have 12' abs pipe want cut 3 pices one at 33 3/8 and seccon at 56 5/8 and tird at 39 7/8 the saw at 1/8 what got left<BR>\n" );
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document.write( "12' = 144 inches<BR>\n" );
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document.write( "33 3/8 + 56 5/8 + 39 7/8 = 112 15/8<BR>\n" );
document.write( "= 113\" 7/8<BR>\n" );
document.write( "2 cuts = 1/4\"<BR>\n" );
document.write( "--> 114\" 1/8<BR>\n" );
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document.write( "144\" - 114 7/8 = 29 1/8<BR>\n" );
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