document.write( "Question 627424: what are solutions to the equation ? *have to be square roots !\r
\n" ); document.write( "\n" ); document.write( "(2x+3)^2=10
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Algebra.Com's Answer #394919 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"%282x%2B3%29%5E2=10\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B3=%22%22%2B-sqrt%2810%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B3=sqrt%2810%29\" or \"2x%2B3=-sqrt%2810%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=-3%2Bsqrt%2810%29\" or \"2x=-3-sqrt%2810%29\" Subtract \"3\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-3%2Bsqrt%2810%29%29%2F2\" or \"x=%28-3-sqrt%2810%29%29%2F2\" Divide both sides by 2.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=%28-3%2Bsqrt%2810%29%29%2F2\" or \"x=%28-3-sqrt%2810%29%29%2F2\".\r
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